Optimal. Leaf size=288 \[ \frac {(d+e x)^{-5-2 p} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right ) (4+p)}+\frac {6 c^2 d^2 (d+e x)^{-3-2 p} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right )^3 (2+p) (3+p) (4+p)}+\frac {6 c^3 d^3 (d+e x)^{-2 (1+p)} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right )^4 (1+p) (2+p) (3+p) (4+p)}+\frac {3 c d (d+e x)^{-2 (2+p)} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right )^2 (3+p) (4+p)} \]
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Rubi [A]
time = 0.11, antiderivative size = 288, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 2, integrand size = 39, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.051, Rules used = {672, 664}
\begin {gather*} \frac {6 c^3 d^3 (d+e x)^{-2 (p+1)} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{p+1}}{(p+1) (p+2) (p+3) (p+4) \left (c d^2-a e^2\right )^4}+\frac {6 c^2 d^2 (d+e x)^{-2 p-3} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{p+1}}{(p+2) (p+3) (p+4) \left (c d^2-a e^2\right )^3}+\frac {(d+e x)^{-2 p-5} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{p+1}}{(p+4) \left (c d^2-a e^2\right )}+\frac {3 c d (d+e x)^{-2 (p+2)} \left (x \left (a e^2+c d^2\right )+a d e+c d e x^2\right )^{p+1}}{(p+3) (p+4) \left (c d^2-a e^2\right )^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 664
Rule 672
Rubi steps
\begin {align*} \int (d+e x)^{-5-2 p} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^p \, dx &=\frac {(d+e x)^{-5-2 p} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right ) (4+p)}+\frac {(3 c d) \int (d+e x)^{-4-2 p} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^p \, dx}{\left (c d^2-a e^2\right ) (4+p)}\\ &=\frac {(d+e x)^{-5-2 p} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right ) (4+p)}+\frac {3 c d (d+e x)^{-2 (2+p)} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right )^2 (3+p) (4+p)}+\frac {\left (6 c^2 d^2\right ) \int (d+e x)^{-3-2 p} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^p \, dx}{\left (c d^2-a e^2\right )^2 (3+p) (4+p)}\\ &=\frac {(d+e x)^{-5-2 p} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right ) (4+p)}+\frac {6 c^2 d^2 (d+e x)^{-3-2 p} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right )^3 (2+p) (3+p) (4+p)}+\frac {3 c d (d+e x)^{-2 (2+p)} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right )^2 (3+p) (4+p)}+\frac {\left (6 c^3 d^3\right ) \int (d+e x)^{-2-2 p} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^p \, dx}{\left (c d^2-a e^2\right )^3 (2+p) (3+p) (4+p)}\\ &=\frac {(d+e x)^{-5-2 p} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right ) (4+p)}+\frac {6 c^2 d^2 (d+e x)^{-3-2 p} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right )^3 (2+p) (3+p) (4+p)}+\frac {6 c^3 d^3 (d+e x)^{-2 (1+p)} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right )^4 (1+p) (2+p) (3+p) (4+p)}+\frac {3 c d (d+e x)^{-2 (2+p)} \left (a d e+\left (c d^2+a e^2\right ) x+c d e x^2\right )^{1+p}}{\left (c d^2-a e^2\right )^2 (3+p) (4+p)}\\ \end {align*}
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Mathematica [A]
time = 0.13, size = 217, normalized size = 0.75 \begin {gather*} \frac {(d+e x)^{-5-2 p} ((a e+c d x) (d+e x))^{1+p} \left (-a^3 e^6 \left (6+11 p+6 p^2+p^3\right )+3 a^2 c d e^4 \left (2+3 p+p^2\right ) (d (4+p)+e x)-3 a c^2 d^2 e^2 (1+p) \left (d^2 \left (12+7 p+p^2\right )+2 d e (4+p) x+2 e^2 x^2\right )+c^3 d^3 \left (d^3 \left (24+26 p+9 p^2+p^3\right )+3 d^2 e \left (12+7 p+p^2\right ) x+6 d e^2 (4+p) x^2+6 e^3 x^3\right )\right )}{\left (c d^2-a e^2\right )^4 (1+p) (2+p) (3+p) (4+p)} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(744\) vs.
\(2(292)=584\).
time = 0.90, size = 745, normalized size = 2.59
method | result | size |
gosper | \(-\frac {\left (c d x +a e \right ) \left (e x +d \right )^{-4-2 p} \left (a^{3} e^{6} p^{3}-3 a^{2} c \,d^{2} e^{4} p^{3}-3 a^{2} c d \,e^{5} p^{2} x +3 a \,c^{2} d^{4} e^{2} p^{3}+6 a \,c^{2} d^{3} e^{3} p^{2} x +6 a \,c^{2} d^{2} e^{4} p \,x^{2}-c^{3} d^{6} p^{3}-3 c^{3} d^{5} e \,p^{2} x -6 c^{3} d^{4} e^{2} p \,x^{2}-6 c^{3} d^{3} e^{3} x^{3}+6 a^{3} e^{6} p^{2}-21 a^{2} c \,d^{2} e^{4} p^{2}-9 a^{2} c d \,e^{5} p x +24 a \,c^{2} d^{4} e^{2} p^{2}+30 a \,c^{2} d^{3} e^{3} p x +6 a \,c^{2} d^{2} e^{4} x^{2}-9 c^{3} d^{6} p^{2}-21 c^{3} d^{5} e p x -24 c^{3} d^{4} e^{2} x^{2}+11 a^{3} e^{6} p -42 a^{2} c \,d^{2} e^{4} p -6 a^{2} c d \,e^{5} x +57 a \,c^{2} d^{4} e^{2} p +24 a \,c^{2} d^{3} e^{3} x -26 c^{3} d^{6} p -36 c^{3} d^{5} e x +6 e^{6} a^{3}-24 e^{4} d^{2} a^{2} c +36 d^{4} e^{2} c^{2} a -24 d^{6} c^{3}\right ) \left (c d e \,x^{2}+a \,e^{2} x +c \,d^{2} x +a d e \right )^{p}}{a^{4} e^{8} p^{4}-4 a^{3} c \,d^{2} e^{6} p^{4}+6 a^{2} c^{2} d^{4} e^{4} p^{4}-4 a \,c^{3} d^{6} e^{2} p^{4}+c^{4} d^{8} p^{4}+10 a^{4} e^{8} p^{3}-40 a^{3} c \,d^{2} e^{6} p^{3}+60 a^{2} c^{2} d^{4} e^{4} p^{3}-40 a \,c^{3} d^{6} e^{2} p^{3}+10 c^{4} d^{8} p^{3}+35 a^{4} e^{8} p^{2}-140 a^{3} c \,d^{2} e^{6} p^{2}+210 a^{2} c^{2} d^{4} e^{4} p^{2}-140 a \,c^{3} d^{6} e^{2} p^{2}+35 c^{4} d^{8} p^{2}+50 a^{4} e^{8} p -200 a^{3} c \,d^{2} e^{6} p +300 a^{2} c^{2} d^{4} e^{4} p -200 a \,c^{3} d^{6} e^{2} p +50 c^{4} d^{8} p +24 a^{4} e^{8}-96 a^{3} c \,d^{2} e^{6}+144 a^{2} c^{2} d^{4} e^{4}-96 a \,c^{3} d^{6} e^{2}+24 c^{4} d^{8}}\) | \(745\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 1017 vs.
\(2 (296) = 592\).
time = 4.85, size = 1017, normalized size = 3.53 \begin {gather*} -\frac {{\left ({\left (a^{4} p^{3} + 6 \, a^{4} p^{2} + 11 \, a^{4} p + 6 \, a^{4}\right )} x e^{8} - {\left (c^{4} d^{8} p^{3} + 9 \, c^{4} d^{8} p^{2} + 26 \, c^{4} d^{8} p + 24 \, c^{4} d^{8}\right )} x + {\left (a^{4} d p^{3} + 6 \, a^{4} d p^{2} + 11 \, a^{4} d p + 6 \, a^{4} d + {\left (a^{3} c d p^{3} + 3 \, a^{3} c d p^{2} + 2 \, a^{3} c d p\right )} x^{2}\right )} e^{7} - {\left (3 \, {\left (a^{2} c^{2} d^{2} p^{2} + a^{2} c^{2} d^{2} p\right )} x^{3} + 2 \, {\left (a^{3} c d^{2} p^{3} + 9 \, a^{3} c d^{2} p^{2} + 20 \, a^{3} c d^{2} p + 12 \, a^{3} c d^{2}\right )} x\right )} e^{6} + 3 \, {\left (2 \, a c^{3} d^{3} p x^{4} - a^{3} c d^{3} p^{3} - 7 \, a^{3} c d^{3} p^{2} - 14 \, a^{3} c d^{3} p - 8 \, a^{3} c d^{3} - {\left (a^{2} c^{2} d^{3} p^{3} + 6 \, a^{2} c^{2} d^{3} p^{2} + 5 \, a^{2} c^{2} d^{3} p\right )} x^{2}\right )} e^{5} - 3 \, {\left (2 \, c^{4} d^{4} x^{5} - 2 \, {\left (a c^{3} d^{4} p^{2} + 5 \, a c^{3} d^{4} p\right )} x^{3} - 3 \, {\left (a^{2} c^{2} d^{4} p^{2} + 5 \, a^{2} c^{2} d^{4} p + 4 \, a^{2} c^{2} d^{4}\right )} x\right )} e^{4} + 3 \, {\left (a^{2} c^{2} d^{5} p^{3} + 8 \, a^{2} c^{2} d^{5} p^{2} + 19 \, a^{2} c^{2} d^{5} p + 12 \, a^{2} c^{2} d^{5} - 2 \, {\left (c^{4} d^{5} p + 5 \, c^{4} d^{5}\right )} x^{4} + {\left (a c^{3} d^{5} p^{3} + 9 \, a c^{3} d^{5} p^{2} + 20 \, a c^{3} d^{5} p\right )} x^{2}\right )} e^{3} - {\left (3 \, {\left (c^{4} d^{6} p^{2} + 9 \, c^{4} d^{6} p + 20 \, c^{4} d^{6}\right )} x^{3} - 2 \, {\left (a c^{3} d^{6} p^{3} + 6 \, a c^{3} d^{6} p^{2} + 5 \, a c^{3} d^{6} p - 12 \, a c^{3} d^{6}\right )} x\right )} e^{2} - {\left (a c^{3} d^{7} p^{3} + 9 \, a c^{3} d^{7} p^{2} + 26 \, a c^{3} d^{7} p + 24 \, a c^{3} d^{7} + {\left (c^{4} d^{7} p^{3} + 12 \, c^{4} d^{7} p^{2} + 47 \, c^{4} d^{7} p + 60 \, c^{4} d^{7}\right )} x^{2}\right )} e\right )} {\left (c d^{2} x + a x e^{2} + {\left (c d x^{2} + a d\right )} e\right )}^{p} {\left (x e + d\right )}^{-2 \, p - 5}}{c^{4} d^{8} p^{4} + 10 \, c^{4} d^{8} p^{3} + 35 \, c^{4} d^{8} p^{2} + 50 \, c^{4} d^{8} p + 24 \, c^{4} d^{8} + {\left (a^{4} p^{4} + 10 \, a^{4} p^{3} + 35 \, a^{4} p^{2} + 50 \, a^{4} p + 24 \, a^{4}\right )} e^{8} - 4 \, {\left (a^{3} c d^{2} p^{4} + 10 \, a^{3} c d^{2} p^{3} + 35 \, a^{3} c d^{2} p^{2} + 50 \, a^{3} c d^{2} p + 24 \, a^{3} c d^{2}\right )} e^{6} + 6 \, {\left (a^{2} c^{2} d^{4} p^{4} + 10 \, a^{2} c^{2} d^{4} p^{3} + 35 \, a^{2} c^{2} d^{4} p^{2} + 50 \, a^{2} c^{2} d^{4} p + 24 \, a^{2} c^{2} d^{4}\right )} e^{4} - 4 \, {\left (a c^{3} d^{6} p^{4} + 10 \, a c^{3} d^{6} p^{3} + 35 \, a c^{3} d^{6} p^{2} + 50 \, a c^{3} d^{6} p + 24 \, a c^{3} d^{6}\right )} e^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: SystemError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 2.06, size = 1036, normalized size = 3.60 \begin {gather*} {\left (c\,d\,e\,x^2+\left (c\,d^2+a\,e^2\right )\,x+a\,d\,e\right )}^p\,\left (\frac {6\,c^4\,d^4\,e^4\,x^5}{{\left (a\,e^2-c\,d^2\right )}^4\,{\left (d+e\,x\right )}^{2\,p+5}\,\left (p^4+10\,p^3+35\,p^2+50\,p+24\right )}-\frac {x\,\left (a^4\,e^8\,p^3+6\,a^4\,e^8\,p^2+11\,a^4\,e^8\,p+6\,a^4\,e^8-2\,a^3\,c\,d^2\,e^6\,p^3-18\,a^3\,c\,d^2\,e^6\,p^2-40\,a^3\,c\,d^2\,e^6\,p-24\,a^3\,c\,d^2\,e^6+9\,a^2\,c^2\,d^4\,e^4\,p^2+45\,a^2\,c^2\,d^4\,e^4\,p+36\,a^2\,c^2\,d^4\,e^4+2\,a\,c^3\,d^6\,e^2\,p^3+12\,a\,c^3\,d^6\,e^2\,p^2+10\,a\,c^3\,d^6\,e^2\,p-24\,a\,c^3\,d^6\,e^2-c^4\,d^8\,p^3-9\,c^4\,d^8\,p^2-26\,c^4\,d^8\,p-24\,c^4\,d^8\right )}{{\left (a\,e^2-c\,d^2\right )}^4\,{\left (d+e\,x\right )}^{2\,p+5}\,\left (p^4+10\,p^3+35\,p^2+50\,p+24\right )}-\frac {a\,d\,e\,\left (a^3\,e^6\,p^3+6\,a^3\,e^6\,p^2+11\,a^3\,e^6\,p+6\,a^3\,e^6-3\,a^2\,c\,d^2\,e^4\,p^3-21\,a^2\,c\,d^2\,e^4\,p^2-42\,a^2\,c\,d^2\,e^4\,p-24\,a^2\,c\,d^2\,e^4+3\,a\,c^2\,d^4\,e^2\,p^3+24\,a\,c^2\,d^4\,e^2\,p^2+57\,a\,c^2\,d^4\,e^2\,p+36\,a\,c^2\,d^4\,e^2-c^3\,d^6\,p^3-9\,c^3\,d^6\,p^2-26\,c^3\,d^6\,p-24\,c^3\,d^6\right )}{{\left (a\,e^2-c\,d^2\right )}^4\,{\left (d+e\,x\right )}^{2\,p+5}\,\left (p^4+10\,p^3+35\,p^2+50\,p+24\right )}+\frac {6\,c^3\,d^3\,e^3\,x^4\,\left (5\,c\,d^2-a\,e^2\,p+c\,d^2\,p\right )}{{\left (a\,e^2-c\,d^2\right )}^4\,{\left (d+e\,x\right )}^{2\,p+5}\,\left (p^4+10\,p^3+35\,p^2+50\,p+24\right )}+\frac {3\,c^2\,d^2\,e^2\,x^3\,\left (a^2\,e^4\,p^2+a^2\,e^4\,p-2\,a\,c\,d^2\,e^2\,p^2-10\,a\,c\,d^2\,e^2\,p+c^2\,d^4\,p^2+9\,c^2\,d^4\,p+20\,c^2\,d^4\right )}{{\left (a\,e^2-c\,d^2\right )}^4\,{\left (d+e\,x\right )}^{2\,p+5}\,\left (p^4+10\,p^3+35\,p^2+50\,p+24\right )}+\frac {c\,d\,e\,x^2\,\left (-a^3\,e^6\,p^3-3\,a^3\,e^6\,p^2-2\,a^3\,e^6\,p+3\,a^2\,c\,d^2\,e^4\,p^3+18\,a^2\,c\,d^2\,e^4\,p^2+15\,a^2\,c\,d^2\,e^4\,p-3\,a\,c^2\,d^4\,e^2\,p^3-27\,a\,c^2\,d^4\,e^2\,p^2-60\,a\,c^2\,d^4\,e^2\,p+c^3\,d^6\,p^3+12\,c^3\,d^6\,p^2+47\,c^3\,d^6\,p+60\,c^3\,d^6\right )}{{\left (a\,e^2-c\,d^2\right )}^4\,{\left (d+e\,x\right )}^{2\,p+5}\,\left (p^4+10\,p^3+35\,p^2+50\,p+24\right )}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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